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authorMazdak Farrokhzad <twingoow@gmail.com>2019-04-12 12:18:07 +0200
committerGitHub <noreply@github.com>2019-04-12 12:18:07 +0200
commitcb7079fe72c16097ee3a51b986f6058f85d583d4 (patch)
treea1fbd215ef20fc64a79a20d325ee75ca914deeaf
parent257dbb826d0000f7d56c71fb7d93b5de288a157e (diff)
parentaefc1581b125876f37c652f84fddc81b0b25fe12 (diff)
downloadrust-cb7079fe72c16097ee3a51b986f6058f85d583d4.tar.gz
rust-cb7079fe72c16097ee3a51b986f6058f85d583d4.zip
Rollup merge of #59889 - andrewbanchich:minor-text-fixes, r=estebank
Update diagnostics.rs

Add `a` and other minor text improvements
-rw-r--r--src/librustc_mir/diagnostics.rs4
1 files changed, 2 insertions, 2 deletions
diff --git a/src/librustc_mir/diagnostics.rs b/src/librustc_mir/diagnostics.rs
index e1b66312da2..c8836fe5193 100644
--- a/src/librustc_mir/diagnostics.rs
+++ b/src/librustc_mir/diagnostics.rs
@@ -2307,10 +2307,10 @@ let q = *p;
 ```
 
 Here, the expression `&foo()` is borrowing the expression
-`foo()`. As `foo()` is call to a function, and not the name of
+`foo()`. As `foo()` is a call to a function, and not the name of
 a variable, this creates a **temporary** -- that temporary stores
 the return value from `foo()` so that it can be borrowed.
-So you might imagine that `let p = bar(&foo())` is equivalent
+You could imagine that `let p = bar(&foo());` is equivalent
 to this:
 
 ```compile_fail,E0597