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| author | Matthias Krüger <matthias.krueger@famsik.de> | 2021-12-11 17:35:23 +0100 |
|---|---|---|
| committer | GitHub <noreply@github.com> | 2021-12-11 17:35:23 +0100 |
| commit | 433a13b47347849dbc8c5d5300b98b95be7fb2c9 (patch) | |
| tree | 1c330cf7465ec6adcdb2b607594b65f80284eb73 /compiler/rustc_codegen_llvm/src | |
| parent | b9a37ad0d995c71518629b032f8e816e1efa8bca (diff) | |
| parent | e27315268b10c9ef2f4c3d815dfc79f513327def (diff) | |
| download | rust-433a13b47347849dbc8c5d5300b98b95be7fb2c9.tar.gz rust-433a13b47347849dbc8c5d5300b98b95be7fb2c9.zip | |
Rollup merge of #83174 - camelid:borrow-help, r=oli-obk
Suggest using a temporary variable to fix borrowck errors
Fixes #77834.
In Rust, nesting method calls with both require `&mut` access to `self`
produces a borrow-check error:
error[E0499]: cannot borrow `*self` as mutable more than once at a time
--> src/lib.rs:7:14
|
7 | self.foo(self.bar());
| ---------^^^^^^^^^^-
| | | |
| | | second mutable borrow occurs here
| | first borrow later used by call
| first mutable borrow occurs here
That's because Rust has a left-to-right evaluation order, and the method
receiver is passed first. Thus, the argument to the method cannot then
mutate `self`.
There's an easy solution to this error: just extract a local variable
for the inner argument:
let tmp = self.bar();
self.foo(tmp);
However, the error doesn't give any suggestion of how to solve the
problem. As a result, new users may assume that it's impossible to
express their code correctly and get stuck.
This commit adds a (non-structured) suggestion to extract a local
variable for the inner argument to solve the error. The suggestion uses
heuristics that eliminate most false positives, though there are a few
false negatives (cases where the suggestion should be emitted but is
not). Those other cases can be implemented in a future change.
Diffstat (limited to 'compiler/rustc_codegen_llvm/src')
0 files changed, 0 insertions, 0 deletions
