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authorJim Blandy <jimb@red-bean.com>2012-09-04 00:40:18 -0700
committerJim Blandy <jimb@red-bean.com>2012-09-04 01:12:12 -0700
commit959f76ddeb795298b88ef42da0c69fa5198f4fe8 (patch)
tree22e49b28438e5e986a2bb3056dd24bb95b7c04e4 /doc
parent80c4f74c29ede062909db2b048b5b75820730994 (diff)
downloadrust-959f76ddeb795298b88ef42da0c69fa5198f4fe8.tar.gz
rust-959f76ddeb795298b88ef42da0c69fa5198f4fe8.zip
In DuplexStream explanation: change 'There' to 'The'.
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diff --git a/doc/tutorial.md b/doc/tutorial.md
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@@ -2593,7 +2593,7 @@ let result = port.recv();
 ## Creating a task with a bi-directional communication path
 
 A very common thing to do is to spawn a child task where the parent
-and child both need to exchange messages with each other. There
+and child both need to exchange messages with each other. The
 function `std::comm::DuplexStream()` supports this pattern.  We'll
 look briefly at how it is used.