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| author | Jim Blandy <jimb@red-bean.com> | 2012-09-04 00:40:18 -0700 |
|---|---|---|
| committer | Jim Blandy <jimb@red-bean.com> | 2012-09-04 01:12:12 -0700 |
| commit | 959f76ddeb795298b88ef42da0c69fa5198f4fe8 (patch) | |
| tree | 22e49b28438e5e986a2bb3056dd24bb95b7c04e4 /doc | |
| parent | 80c4f74c29ede062909db2b048b5b75820730994 (diff) | |
| download | rust-959f76ddeb795298b88ef42da0c69fa5198f4fe8.tar.gz rust-959f76ddeb795298b88ef42da0c69fa5198f4fe8.zip | |
In DuplexStream explanation: change 'There' to 'The'.
Diffstat (limited to 'doc')
| -rw-r--r-- | doc/tutorial.md | 2 |
1 files changed, 1 insertions, 1 deletions
diff --git a/doc/tutorial.md b/doc/tutorial.md index 4743e384633..e639ce6e9f4 100644 --- a/doc/tutorial.md +++ b/doc/tutorial.md @@ -2593,7 +2593,7 @@ let result = port.recv(); ## Creating a task with a bi-directional communication path A very common thing to do is to spawn a child task where the parent -and child both need to exchange messages with each other. There +and child both need to exchange messages with each other. The function `std::comm::DuplexStream()` supports this pattern. We'll look briefly at how it is used. |
