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| author | Mark Rousskov <mark.simulacrum@gmail.com> | 2019-07-15 19:55:06 -0400 |
|---|---|---|
| committer | GitHub <noreply@github.com> | 2019-07-15 19:55:06 -0400 |
| commit | ee8194002e47b1a6103c7a8f5d592c625b5efba7 (patch) | |
| tree | 05019e5a7dbf634a378f590134da92b2918000e1 /src/test/incremental/thinlto | |
| parent | caf10b5ffe6977e79f8d5f1bb407d99d2b015b4a (diff) | |
| parent | 0c981e0a8a01426dbcac895d67dd33db7f5b6ff4 (diff) | |
| download | rust-ee8194002e47b1a6103c7a8f5d592c625b5efba7.tar.gz rust-ee8194002e47b1a6103c7a8f5d592c625b5efba7.zip | |
Rollup merge of #62639 - immunant:invariant_valistimpl, r=eddyb
Make VaListImpl<'f> invariant over the 'f lifetime After doing some research on variance and going back to look at `VaList` and `VaListImpl`, I realized that `VaList<'a, 'f>` is invariant over the `'f` lifetime (and covariant over `'a`), but `VaListImpl<'f>` isn't invariant but probably should be. This patch makes `VaListImpl<'f>` invariant over `'f`. r? @eddyb cc @dlrobertson
Diffstat (limited to 'src/test/incremental/thinlto')
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