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authorMazdak Farrokhzad <twingoow@gmail.com>2019-07-25 23:20:56 +0200
committerGitHub <noreply@github.com>2019-07-25 23:20:56 +0200
commit008d9d0feaec231fa2fe16468d2d44714e765700 (patch)
tree90090a30dc424c16e8d6729251661f5afa0e0515 /src/test/ui/thinlto
parentdbd0028dcc68b0d3fb3d50dca83e59a4abff7a3c (diff)
parent5f7768a976edc296c62479b936993b4dc9af065b (diff)
downloadrust-008d9d0feaec231fa2fe16468d2d44714e765700.tar.gz
rust-008d9d0feaec231fa2fe16468d2d44714e765700.zip
Rollup merge of #62528 - SimonSapin:concat, r=alexcrichton
Add joining slices of slices with a slice separator, not just a single item

https://github.com/rust-lang/rust/issues/27747#issuecomment-294525391
> It's kinda annoying to be able to join strings with a str (which can have multiple chars), but joining a slice of slices, you can only join with a single element.

This turns out to be fixable, with some possible inference regressions.

# TL;DR

Related trait(s) are unstable and tracked at https://github.com/rust-lang/rust/issues/27747, but the `[T]::join` method that is being extended here is already stable.

Example use of the new insta-stable functionality:

```rust
let nested: Vec<Vec<Foo>> = /* … */;
let separator: &[Foo] = /* … */;  // Previously: could only be a single &Foo
nested.join(separator)
```

Complete API affected by this PR, after changes:

```rust
impl<T> [T] {
    pub fn concat<Item: ?Sized>(&self) -> <Self as Concat<Item>>::Output
        where Self: Concat<Item>
    {
        Concat::concat(self)
    }
    pub fn join<Separator>(&self, sep: Separator) -> <Self as Join<Separator>>::Output
        where Self: Join<Separator>
    {
        Join::join(self, sep)
    }
}

// The `Item` parameter is only useful for the the slice-of-slices impl.
pub trait Concat<Item: ?Sized> {
    type Output;
    fn concat(slice: &Self) -> Self::Output;
}

pub trait Join<Separator> {
    type Output;
    fn join(slice: &Self, sep: Separator) -> Self::Output;
}

impl<T: Clone, V: Borrow<[T]>> Concat<T> for [V] {
    type Output = Vec<T>;
}

impl<T: Clone, V: Borrow<[T]>> Join<&'_ T> for [V] {
    type Output = Vec<T>;
}

// New functionality here!
impl<T: Clone, V: Borrow<[T]>> Join<&'_ [T]> for [V] {
    type Output = Vec<T>;
}

impl<S: Borrow<str>> Concat<str> for [S] {
    type Output = String;
}

impl<S: Borrow<str>> Join<&'_ str> for [S] {
    type Output = String;
}
```

# Details

After https://github.com/rust-lang/rust/pull/62403 but before this PR, the API is:

```rust
impl<T> [T] {
    pub fn concat<Separator: ?Sized>(&self) -> T::Output
        where T: SliceConcat<Separator>
    {
        SliceConcat::concat(self)
    }

    pub fn join<Separator: ?Sized>(&self, sep: &Separator) -> T::Output
        where T: SliceConcat<Separator>
    {
        SliceConcat::join(self, sep)
    }
}

pub trait SliceConcat<Separator: ?Sized>: Sized {
    type Output;
    fn concat(slice: &[Self]) -> Self::Output;
    fn join(slice: &[Self], sep: &Separator) -> Self::Output;
}

impl<T: Clone, V: Borrow<[T]>> SliceConcat<T> for V {
    type Output = Vec<T>;
}

impl<S: Borrow<str>> SliceConcat<str> for S {
    type Output = String;
}
```

By adding a trait impl we should be able to accept a slice of `T` as the separator, as an alternative to a single `T` value.

In a `some_slice.join(some_separator)` call, trait resolution will pick an impl or the other based on the type of `some_separator`. In `some_slice.concat()` however there is no separator, so this call would become ambiguous. Some regression in type inference or trait resolution may be acceptable on principle, but requiring a turbofish for every single call to `concat` isn’t great.

The solution to that is splitting the `SliceConcat` trait into two `Concat` and `Join` traits, one for each eponymous method. Only `Join` would gain a new impl, so that `some_slice.concat()` would not become ambiguous.

Now, at the trait level the `Concat` trait does not need a `Separator` parameter anymore. However, simply removing it causes one of the impls not to be accepted anymore:

```rust
error[E0207]: the type parameter `T` is not constrained by the impl trait, self type, or predicates
  --> src/liballoc/slice.rs:608:6
    |
608 | impl<T: Clone, V: Borrow<[T]>> Concat for [V] {
    |      ^ unconstrained type parameter
```

This makes sense: if `[V]::concat` is a method that is itself not generic, then its return type (which is the `Concat::Output` associated type) needs to be determined based on solely `V`. And although there is no such type in the standard library, there is nothing stopping another crate from defining a `V` type that implements both `Borrow<[Foo]>` and `Borrow<[Bar]>`. It might not be a good idea, but it’s possible. Both would apply here, and there would be no way to determine `T`.

This could be a warning sign that this API is too generic. Perhaps we’d be better off having one less type variable, and only implement `Concat for [&'_ [T]]` and `Concat for [Vec<T>]` etc. However this aspect of `[V]::concat` is already stable, so we’re stuck with it.

The solution is to keep a dummy type parameter on the `Concat` trait. That way, if a type has multiple `Borrow<[_]>` impls, it’ll end up with multiple corresponding `Concat<_>` impls.

In `impl<S: Borrow<str>> Concat<str> for [S]`, the second occurrence of `str` is not meaningful. It could be any type. As long as there is only once such type with an applicable impl, trait resolution will be appeased without demanding turbofishes.

# Joining strings with `char`

For symmetry I also tried adding this impl (because why not):

```rust
impl<S: Borrow<str>> Join<char> for [S] {
    type Output = String;
}
```

This immediately caused an inference regression in a dependency of rustc:

```rust
error[E0277]: the trait bound `std::string::String: std::borrow::Borrow<[std::string::String]>` is not satisfied
   --> /home/simon/.cargo/registry/src/github.com-1ecc6299db9ec823/getopts-0.2.19/src/lib.rs:595:37
    |
595 |             row.push_str(&desc_rows.join(&desc_sep));
    |                                     ^^^^ the trait `std::borrow::Borrow<[std::string::String]>` is not implemented for `std::string::String`
    |
    = help: the following implementations were found:
              <std::string::String as std::borrow::Borrow<str>>
    = note: required because of the requirements on the impl of `std::slice::Join<&std::string::String>` for `[std::string::String]`
```

In the context of this code, two facts are known:

* `desc_rows` is a `Vec<String>`
* `desc_sep` is a `String`

Previously the first fact alone reduces the resolution of `join` to only one solution, where its argument it expected to be `&str`. Then, `&String` is coerced to `&str`.

With the new `Join` impl, the first fact leavs two applicable impls where the separator can be either `&str` or `char`. But `&String` is neither of these things. It appears that possible coercions are not accounted for, in the search for a solution in trait resolution.

I have not included this new impl in this PR. It’s still possible to add later, but the `getopts` breakage does not need to block the rest of the PR. And the functionality easy for end-user to duplicate: `slice_of_strings.join(&*char_separator.encode_utf8(&mut [0_u8, 4]))`

The `&*` part of that last code snippet is another case of the same issue: `encode_utf8` returns `&mut str` which can be coerced to `&str`, but isn’t when trait resolution is ambiguous.
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