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Point at coercion reason for `if` expressions without else clause if caused by return type
```
error[E0317]: if may be missing an else clause
--> $DIR/if-without-else-as-fn-expr.rs:2:5
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LL | fn foo(bar: usize) -> usize {
| ----- found `usize` because of this return type
LL | / if bar % 5 == 0 {
LL | | return 3;
LL | | }
| |_____^ expected (), found usize
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= note: expected type `()`
found type `usize`
= note: `if` expressions without `else` must evaluate to `()`
```
Fix #25228.
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```
error[E0317]: if may be missing an else clause
--> $DIR/if-without-else-as-fn-expr.rs:2:5
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LL | fn foo(bar: usize) -> usize {
| ----- found `usize` because of this return type
LL | / if bar % 5 == 0 {
LL | | return 3;
LL | | }
| |_____^ expected (), found usize
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= note: expected type `()`
found type `usize`
= note: `if` expressions without `else` must evaluate to `()`
```
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Replace "integral variable" with "integer" and replace
"floating-point variable" with "floating-point number" to make the
message less confusing.
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